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Author More PHP! isset()
Laney
Member
Registered: 6th May 03
Location: Leeds
User status: Offline
   13th Jul 07 at 17:54   View User's Profile U2U Member Reply With Quote
Just checking I'm using this right:

if (isset($var1, $var2, $var3))
{

echo ("Woohoo!");

}

That'll check that all variables are present, correct?

Is there any way of generating an error based on which variable is missing? Apart from using lots of IFs?

 
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