cpcrampton
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Registered: 16th Feb 07
Location: Stirling
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Hello AK
I worked this out for you.
GH = 131kn and it is in compression.
reaction at A = 113kn
you can confirm by using this link.
http://www.jhu.edu/virtlab/bridge/bridge.htm
hope this helps you in the future.
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AK
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Registered: 5th Jul 00
Location: Aberdeen City
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cheers, that app is quite handy...
It agrees with my answers for reactions and AF/AC.
But still not fully following how to get 132 for GH.
I've worked it out on the prev page... which part of the working is to shit?
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cpcrampton
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Location: Stirling
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One other thing. if you are just getting into this i recommend getting a book.
This will take you from very simple beam elements through to full on bridge design (resonance, vibration etc.)
The book :-
"McGraw-Hill Series In Structural Engineering & Mechanics"
If you require any input for anything engineering related feel free to ask.
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AK
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Location: Aberdeen City
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using that java app shows the load GH to be 197kN
2x113.3 - 30 = 197
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cpcrampton
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Location: Stirling
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SUM Md = 0
Reaction Force at A = 113.3kN
(113.3*2m)-(30kN*1m)-(Fgh*1m) = 0
so 226.6-30-?=0
so ? = 226.6-30 = 196.6KN
You were screwing up by mutiplying fGH by 2. why were you doing that? its one element from D not 2. ignore my first answer of 132 i was looking at someone elses reply when i was writing it.
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cpcrampton
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quote: Originally posted by AK
ok,
so I'll have a bash again...
Taking moments about D
SUM Md = 0
Reaction Force at A = 113.3kN
-(113.3*2m)+(30kN*1m)-(Fgh*1m) = 0
so Fgh = -196.6kN
Na, thats not fucking right
you had it correct here ^^^
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AK
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Location: Aberdeen City
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yup.... that was my whole issue....
I'd had it right, but still think its too easy for the marks!!!
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AK
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Location: Aberdeen City
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oh, and I was popping 2 in there as it was 2m from A... but thats just daft
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LeeM
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Location: Liverpool
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I think you need to do it all from one point, aren't angular forces calculated from the components of a vector? I did this ages ago so without digging some paperwork out I can't remember exactly lol
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cpcrampton
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Location: Stirling
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Lee you are correct, you can also do it point by point , using nodal analysis where you split the force up across each member using like 30kn/sin45 give the force down one member. so you would pick a point and draw a free body diagram where the sum of the forces = 0 then you move to the next point and do it one by one.
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LeeM
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There we go, that's more what I was getting at
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AK
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Location: Aberdeen City
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yup - nodal (method of joints)... that was the method I had to use to get the forces for AF and AC. Prevoius part of the Q
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AK
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oh, thanks by the way
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cpcrampton
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Location: Stirling
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no worries. I will introduce myself next time i see you at knockhill. Time attack !
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AK
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Location: Aberdeen City
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I wont be there Working in Norway.
Fee will be there though...
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cpcrampton
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Registered: 16th Feb 07
Location: Stirling
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aww well, unlucky. il be in stavanger very soon, got ops meetings with conocophillips for a development well with some prototype turbodrills.
[Edited on 06-06-2012 by cpcrampton]
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AK
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Location: Aberdeen City
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I'll be in Stavanger on the 18/19th June
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