Ian
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4000 x 8 is 32000 bits per second
3 seconds
32000 x 3 = 96000 bits in the sample
roughly = 93.75kb but that isn't in the answers.
Edit
96000 bits
96000 / 8 = 12000 bytes = 11.7kb
So you can disregard the sample rate by chance in this question, each sample is exactly 1 byte so the same size does equate to the data size.
[Edited on 23-12-2009 by Ian]
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Ian
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quote:
Originally posted by Dione J
you need to decide how many levels of precision you will use.
Yes, which for 256 distinct levels you would need an 8 bit binary number, so each sample is 8 bits long.
So you multiply the number of samples by 8 to find the number of bits that the data occupies.
Then you divide by 8 because you're working in bytes and there are 8 bits in a byte.
F is right.
[Edited on 23-12-2009 by Ian]
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Dione J
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A communications network (Network P) has a throughput of approximately 28 Mbps and a second communication network (Network Q) has a throughput of approximately 650 kbps. Which of the statements below gives the best estimate for comparing the two networks?
Choose one option from below and mark the appropriate cell in row 12.
A Network P has a throughput about twenty times greater than Network Q.
B Network P has a throughput about forty times greater than Network Q.
C Network P has a throughput about ten times greater than Network Q.
D Network Q has a throughput about twenty times greater than Network P.
E Network Q has a throughput about forty times greater than Network P.
F Network Q has a throughput about ten times greater than Network
*not sure on how to convert the MB to Kpbs
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Ian
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kbps is kilobits per second, divide by 8 to get kilobytes per second.
http://www.matisse.net/bitcalc/
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Dione J
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28/8 = 3.5kbps?
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Ian
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No that is Mbps so if you divide by 8 it'll be Mb per second.
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Dione J
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Confused now, i was trying to convert the mbps into kbps.
So 3.5/8=0.4375kpbs?
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Ian
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8 bits in a byte
1024 kilobytes in a megabyte.
Your method is OK but dividing by 8 converts between mbps and Mb/sec not between mbps and kbps. For the latter, you need 1024.
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Dione J
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So Network P has = 0.273kpbs
(28mbps/1024)
Network Q has = 650kpbs
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Ian
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Not sure, I'll look properly later.
Just find the speeds of both networks in the same unit, then divide the larger by the smaller and it'll tell you how many times faster the quick one is.
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Dione J
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28 x 1024 x 1024 x8 = 2341024
234kbps for Network Q?
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noshua
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28 x 1024 x 1024 x 8 = 234881024 not 2341024
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noshua
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650 kbps = 0.634765625 Mbps (this is network Q)
28 (Network P) / 0.63 (Network Q) = 44.44 so;
Network P is 44.44 times greater than Network Q, thus;
B Network P has a throughput about forty times greater than Network Q.
edit: not fifty times either as 44.44 is rounded down to 40.
edit2: you can use google to convert kbps to mbps via googling (without quotes) "number kbps to mbps". Infact, you can do it with just about any measurement.
[Edited on 24-12-2009 by noshua]
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Root
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do we get the qualification after doing all your work too? 
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