cdcool1
Member
Registered: 9th Jun 02
Location: Scunny
User status: Offline
|
need help, got a maths resit at uni next week, i dont even do maths, but i do electronics, and there shit loads of maths in it.
need help with hyperbolic functions, argand diagrams and possibly complex roots
|
Craig6682
Member
Registered: 8th Apr 03
User status: Offline
|
Sorry mate - no good at maths. Did an bit of Binary on my course that's it.
Good Luck mate.
|
chris_uk
Premium Member
Registered: 8th Jul 03
User status: Offline
|
i know 2+2 = 4... wait no 8 erm i dunno >  JOKE! no not me m8
|
jm960326
Member
Registered: 24th Aug 02
Location: Rob Cheshire
User status: Offline
|
Post an example, I have done a load of maths at uni, Electrical Engineering stuff.
|
diddon
Member
Registered: 23rd Apr 02
User status: Offline
|
my old mans a maths teacher
|
cdcool1
Member
Registered: 9th Jun 02
Location: Scunny
User status: Offline
|
prove that:
d sinh x = cosh x
d x
for example
[Edited on 06-08-2003 by cdcool1]
|
Craig6682
Member
Registered: 8th Apr 03
User status: Offline
|
|
Jason
Member
Registered: 5th Aug 03
Location: Northern Ireland
User status: Offline
|
|
Tiger
Member
Registered: 12th Jun 01
Location: Leicestershire Drives:Astra VXR
User status: Offline
|
No point - in 2006 theres going to be a nuclear war thats going to wipe out 85% of the human race.
|
chris_uk
Premium Member
Registered: 8th Jul 03
User status: Offline
|
humm... im really really clever...
i use a calculator!
|
cdcool1
Member
Registered: 9th Jun 02
Location: Scunny
User status: Offline
|
another one:
the relationship between the current I (in amps) and voltage V (in volts) of a diode is given by
I(V) = I (source) e^(40V)
where I(source) = 10^-13 amps
Using a Taylor series, find a second order polynomial in the form
i(v) = a0 + a1v + a2v^2
which approximates the behaviou of the current through the diode around an operating voltage of 0.7 volts. Determine the % error using this approximation at a voltage of 0.71 volts
|
diddon
Member
Registered: 23rd Apr 02
User status: Offline
|
good luck m8
|
cdcool1
Member
Registered: 9th Jun 02
Location: Scunny
User status: Offline
|
in other words, i'm fooked!
|
Jason
Member
Registered: 5th Aug 03
Location: Northern Ireland
User status: Offline
|
quote:
Originally posted by cdcool1
another one:
the relationship between the current I (in amps) and voltage V (in volts) of a diode is given by
I(V) = I (source) e^(40V)
where I(source) = 10^-13 amps
Using a Taylor series, find a second order polynomial in the form
i(v) = a0 + a1v + a2v^2
which approximates the behaviou of the current through the diode around an operating voltage of 0.7 volts. Determine the % error using this approximation at a voltage of 0.71 volts
i remember doing somthin like that in physics
|
