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Author Boolean Algebra
cdcool1
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Registered: 9th Jun 02
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18th Mar 04 at 16:59   View User's Profile U2U Member Reply With Quote
Is anyone any good at it?? I've got 3 different equations which i've simplified as much as i can and i cant get them any further but i'm sure they will simplify more.

Cant be arsed to post them up if no-one knows it, so if someone does, then i'll type them up
CorsaLad16v
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Registered: 5th Mar 03
Location: Sheffield UK Drives: VW Golf
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18th Mar 04 at 17:03   View User's Profile U2U Member Reply With Quote
just looked Boolean Algebra up on google, aint got a clue sorryyy
Adam
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18th Mar 04 at 17:05   View User's Profile U2U Member Reply With Quote
post em up
cdcool1
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18th Mar 04 at 17:17   View User's Profile U2U Member Reply With Quote
ok, this is what i've got, more or less straight from the karnaugh (sp) mapping

i know that i can group some, but i think there are some simplifications that can be done other than grouping:

ok, there is no way i can do a "NOT" function in the normal way, so i've used an underline, instead of a line on the top.....

Qa is one term, Qb is one term, Qc is one term

DC = A.R.Qa.Qb.Qc + A.R.Qa.Qb.Qc + A.R.Qa + A.Qa + Qa.Qc

thats the first one
cdcool1
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18th Mar 04 at 17:19   View User's Profile U2U Member Reply With Quote
oops, i've simplified that to:

Dc = Qa.Qb.Qc + A.R.Qa + A.Qa + Qa.Qc

[Edited on 18-03-2004 by cdcool1]

[Edited on 18-03-2004 by cdcool1]
cdcool1
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18th Mar 04 at 17:23   View User's Profile U2U Member Reply With Quote
the second one is:

Db = A.B.R.Qa.Qb.Qc + A.B.R.Qb.Qc + B.R.Qa.Qb.Qc + R.Qb
cdcool1
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18th Mar 04 at 17:27   View User's Profile U2U Member Reply With Quote
In the third one, i've used (+) as EXOR (exclusive OR)

Da = A.B.R.Qa.Qb + B.R.Qc + A.B.R.Qa + B.R.(Qa(+)Qc) + A.B.R.Qb

[Edited on 18-03-2004 by cdcool1]
Joff
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18th Mar 04 at 17:36   View User's Profile U2U Member Reply With Quote
I could have helped a year ago, but thankfully I've wiped all of DeMorgan's laws out of my mind

Commutative laws can seriously SMB.

Google for "Boolean algebra rules" or Boolean algebra laws
danregs
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18th Mar 04 at 19:10   View User's Profile U2U Member Reply With Quote
in those questions above have you used + for an OR and . for an AND yeh mate?
danregs
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18th Mar 04 at 19:37   View User's Profile U2U Member Reply With Quote
well no.2 i got as

R.( (B+Qa).(A+Qc) + B.Qa.Qc + Qb )

if thats any help

hope its right

i did this last year so it should be right as long as my memory aint playin tricks on me
R Lee
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18th Mar 04 at 19:39   View User's Profile U2U Member Reply With Quote
what the fuck???????
groom
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18th Mar 04 at 19:58   View User's Profile U2U Member Reply With Quote
quote:
Originally posted by GoldPenguin
what the fuck???????



what he said

 
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