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Author Anyone fancy helping me with a Trig Question?
Bart
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Registered: 19th Aug 02
Location: Midsomer Norton, Bristol Avon
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30th Nov 04 at 13:51   View User's Profile U2U Member Reply With Quote
hate trig, and this is the only question i got left for my homework this month.
If anyone can help me with it (mainly after the solution+answer) that would be great


Adam
Ian
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Registered: 28th Aug 99
Location: Liverpool
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30th Nov 04 at 14:26   View Garage View User's Profile U2U Member Reply With Quote
Treat it like its 20mm wide for the whole height of the hole, with a thin right-angle triangle at both sides.

If a is the angle

tan a = opp / adj

opposite is the difference between the sizes of ball, ie. 5, split between two sides = 2.5.

adjacent is the distance between the balls which you can work out fairly easily, 61.44 + 6.10 is the distance between the tops, subtract 12.5 then add 10.

That should get you going on question a)

b) is easy also, just get the angle you find for a) and use toa again, just rewrite it to make opp the subject, ie.

adj (tan a) = opp

None of this is checked btw
drunkenfool
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Registered: 7th Feb 03
Location: Hereford Drives: Audi R8 V8
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30th Nov 04 at 14:37   View User's Profile U2U Member Reply With Quote
ill have a look when i get back from my lecture if itsnot done then
Bart
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Location: Midsomer Norton, Bristol Avon
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30th Nov 04 at 15:07   View User's Profile U2U Member Reply With Quote
ok
Bart
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5th Dec 04 at 15:41   View User's Profile U2U Member Reply With Quote
anyone else? :-s
Ian
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Registered: 28th Aug 99
Location: Liverpool
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5th Dec 04 at 15:50   View Garage View User's Profile U2U Member Reply With Quote
Just follow my instructions!

How far did you get through them? Anywhere?
mike_1.2LS96
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Registered: 23rd Oct 03
Location: Darlington | Mazda 323 1.8 Exec
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5th Dec 04 at 16:08   View User's Profile U2U Member Reply With Quote
a) tan-1 0.074
b) 61.44 tan (answer a)

there ya go i think.
Bart
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Registered: 19th Aug 02
Location: Midsomer Norton, Bristol Avon
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5th Dec 04 at 16:41   View User's Profile U2U Member Reply With Quote
any chance you could explain the answers mate in great detail?

i really dont get trig that much, and i need to show my working out
Ian
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Registered: 28th Aug 99
Location: Liverpool
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5th Dec 04 at 16:43   View Garage View User's Profile U2U Member Reply With Quote
Do you know SOHCAHTOA?
Nath
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Registered: 3rd Apr 02
Location: MK
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5th Dec 04 at 16:46   View User's Profile U2U Member Reply With Quote
quote:
Originally posted by Ian
Do you know SOHCAHTOA?


Wow GCSE flashback there
Bart
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5th Dec 04 at 16:48   View User's Profile U2U Member Reply With Quote
yes, but dont really understand it a great deal.
Sin = opp/adj
cos = adj/hyp
etc
Ian
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5th Dec 04 at 17:04   View Garage View User's Profile U2U Member Reply With Quote
Not completely.

If you need to work out an unknown you check what you have first and choose the most appropriate one. Assuming you have the angle of 30, the opposite but not the adjacent then yes:

sin 30 = 5 / adj

Rewrite that to make adj the subject:

adj x (sin 30) = 5

adj = sin 30 / 5

Then just work it out. If you have problems rewriting it, read this a few of these:

http://www.google.co.uk/search?hl=en&q=simultaneous+equations
Mistamist
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Registered: 16th Jul 03
Location: Gillingham, Kent
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5th Dec 04 at 17:10   View User's Profile U2U Member Reply With Quote
quote:
Originally posted by Ian
Do you know SOHCAHTOA?


STOP PLEASE NOW!!!

just saw a vision of my maths teacher Miss Marquiss, she smelt like the gym changing rooms after its raining outside, and im sure she was a close relation of a yeti as she had more facial hair than all of the pubecent lads in her class.

 
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