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Steve

Premium Member

Registered: 30th Mar 02
Location: Worcestershire Drives: Defender
User status: Offline

13th Apr 07 at 07:19

Right basically I have two values that are the same, for arguments sake

$x1 = 200
$x2 = 200

Now i want to use some sort of IF statement or anyother statement you can think of to return a value if $x1 = or is greater than, or less than $x2 by 3

so for instance if $x1 = 198 it would return a vale, if $x = 201 it would return a value, but if $x1 = 190 then it woudnt do you see what im getting at?

I need a value to be return if $x1 is equal to or anywher in between + or - 3 each way of $x2

[Edited on 13-04-2007 by Steve]

Steve

Premium Member

Registered: 30th Mar 02
Location: Worcestershire Drives: Defender
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13th Apr 07 at 07:33

if there was n OR functionto use with IF i could do it easily but i cant find one??

AndyKent

Member

Registered: 3rd Sep 05
User status: Offline

13th Apr 07 at 08:04

if(($x1 >= $x2-3)) && ($x1 <= $x2+3))

Does that work?

[Edited on 13-04-2007 by aPk]

Steve

Premium Member

Registered: 30th Mar 02
Location: Worcestershire Drives: Defender
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13th Apr 07 at 08:15

il try it in a sec, is || an equivalent of OR?

Rus

Member

Registered: 24th Jan 05
Location: SE London, Kent
User status: Offline

13th Apr 07 at 08:16

yeah, thats flash actionscript though isn't it apk?

Steve

Premium Member

Registered: 30th Mar 02
Location: Worcestershire Drives: Defender
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13th Apr 07 at 08:17

thats php aswell

Steve

Premium Member

Registered: 30th Mar 02
Location: Worcestershire Drives: Defender
User status: Offline

13th Apr 07 at 08:18

quote:
Originally posted by aPk
if(($x1 >= $x2-3)) && ($x1 <= $x2+3))

Does that work?

[Edited on 13-04-2007 by aPk]

actually thinking about it that wont work as it will need both satisfying to return a value, that would work if the && weere replaced with an OR of some type. Would || work? ie

if(($x1 >= $x2-3)) || ($x1 <= $x2+3))

Rus

Member

Registered: 24th Jan 05
Location: SE London, Kent
User status: Offline

13th Apr 07 at 08:34

var a:Number = 200;
var b:Number = 196;

if (a + 3 >= b && a - 3 <= b) {
trace("1");
} else {
trace("0");
}

there you go

AndyKent

Member

Registered: 3rd Sep 05
User status: Offline

13th Apr 07 at 09:48

quote:
Originally posted by Steve

quote:
Originally posted by aPk
if(($x1 >= $x2-3)) && ($x1 <= $x2+3))

Does that work?

[Edited on 13-04-2007 by aPk]

actually thinking about it that wont work as it will need both satisfying to return a value, that would work if the && weere replaced with an OR of some type. Would || work? ie

if(($x1 >= $x2-3)) || ($x1 <= $x2+3))

No, because it would always evaluate as true

Ie. the if would ask if a number was larger or smaller than a constant which is always true (is a 50 larger or smaller than 100 - true).

And yes, thats PHP - I don't know flash

Rus - thats exactly what I came up with. Should work I'd have thought...

[Edited on 13-04-2007 by aPk]

AndyKent

Member

Registered: 3rd Sep 05
User status: Offline

13th Apr 07 at 09:52

Thinking about it - you want to know if a number is >= or <= to a number by 3. My if statement will return true if so and not if false.

Sorted

Steve

Premium Member

Registered: 30th Mar 02
Location: Worcestershire Drives: Defender
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13th Apr 07 at 10:03

yeah cheers, iv sorted it and got it to work, but doesnt quite work how id liek so iv abaondoned the idea

AndyKent

Member

Registered: 3rd Sep 05
User status: Offline

13th Apr 07 at 10:03

Rus

Member

Registered: 24th Jan 05
Location: SE London, Kent
User status: Offline

13th Apr 07 at 10:07

AndyKent

Member

Registered: 3rd Sep 05
User status: Offline

13th Apr 07 at 10:10

Wonder if someone can help me though actually....

I want to take a date that a user has entered and turn it into a date suitable to insert into MySQL.

The user would enter the date required (ie. 21/05/07) and it needs to be rearranged to read 2007-05-21 00